Today we're going to learn about energy and all the different types of energy but first we have to find out what energy is!
Energy is the capacity of a physical system to perform work which exists in several other forms such as heat, kinetic or mechanical energy, light, potential energy, electrical or other forms.
http://physics.about.com/od/glossary/g/energy.htm
Potential Energy - the stored energy that is held within the gravitational field.
Kinetic Energy - the energy of motion - it's ability to do work
Thermal Energy - part of the internal energy of a system which is the total present kinetic energy resulting from the random movements of atoms and molecules.
Sound Energy - the energy produced by sound vibrations as they travel through a specific medium.
Sunday, December 12, 2010
Saturday, December 11, 2010
Cannons!~
In History there is only one cannon that I can think of that can be considered the greatest cannon of all time. This cannon was created specifically to bombard London during WWII and was considered 1 of the 3 most special projects that the Germans of encountered. That cannons name was called The Gustav Gun.
The cannon weighed 1,350 tonnes was 43 M in length and 7.1 m in Width.
Its barrel length was an astonishing 32 m!!!
Unbelievably they made several of these huge cannons but at the end of the war were later dismantled.
Anyway you can see that this cannon can cause massive destruction wherever it befalls but there are reasons to its success.
If you can see from the image it has a long barrel that narrows, this is to help force the energy which is the combustion of the cannon to exert as much force to increase the acceleration of the projectile. I'm sure there is more technical things about this cannon but since it was a destructive war machine I was not able to find much specifics on it.
A shell of the Gustav cannon compared to a Russian tank.
The cannon weighed 1,350 tonnes was 43 M in length and 7.1 m in Width.
Its barrel length was an astonishing 32 m!!!
Unbelievably they made several of these huge cannons but at the end of the war were later dismantled.
Anyway you can see that this cannon can cause massive destruction wherever it befalls but there are reasons to its success.
If you can see from the image it has a long barrel that narrows, this is to help force the energy which is the combustion of the cannon to exert as much force to increase the acceleration of the projectile. I'm sure there is more technical things about this cannon but since it was a destructive war machine I was not able to find much specifics on it.
A shell of the Gustav cannon compared to a Russian tank.
Favourite Rollercoaster?
Too be honest I haven't been on very many rollercoasters over the course of my life (if you include those kid rollercoasters which would only go in a oval shape over and over again until the guy controlling it felt like it was a sufficient amount of time) but I have gone on especially good one.
That was the Behemoth!~ ;D
When I went with my friends to Wonderland I wasn't so sure about this one since it was considered the best of them all in Canada (to me at the time it was the worst of them all...) but once you have riden it, it was spectacular!!! There were no loops which I didn't like anyway but there was an amazing amount of inclines especially at the beginning when you slowly inch your way to the top of the incline.
I think the reason why this was considered the best was probably due to the fact that engineers were able to find ways to keep the G forces (gravitational forces) to an appropriate amount which would not make the rider feel like they're being excruciated. They were also able to keep the momentum going by continuously adding inclines that went up and down like a wave.
PS. Has anyone seen where the camera is?! You know, when you're riding the rollercoaster and the people take your photo?? Because I do not know where IT IS >;(
That was the Behemoth!~ ;D
When I went with my friends to Wonderland I wasn't so sure about this one since it was considered the best of them all in Canada (to me at the time it was the worst of them all...) but once you have riden it, it was spectacular!!! There were no loops which I didn't like anyway but there was an amazing amount of inclines especially at the beginning when you slowly inch your way to the top of the incline.
I think the reason why this was considered the best was probably due to the fact that engineers were able to find ways to keep the G forces (gravitational forces) to an appropriate amount which would not make the rider feel like they're being excruciated. They were also able to keep the momentum going by continuously adding inclines that went up and down like a wave.
PS. Has anyone seen where the camera is?! You know, when you're riding the rollercoaster and the people take your photo?? Because I do not know where IT IS >;(
How to add Vectors
Ordinarilywhen I think of vectors I think of area's or a portion of land... Or was that Sectors?? O.o
Well anyway we're here to determine how to add a vector but before we can do that we must first find out what a vector is.
From http://zonalandeducation.com/mstm/physics/mechanics/vectors/vectors.html it states that a vector is a a quatity that has two aspects which has a size, or magnitude, and direction.
So in absolute simple words it pretty much means a straight line.
but it can get more complicated when you add more vectors to other vectors. But before we do that once again we have to find out where the positve sectors are.
As you can see from the diagram North and East is the positive and South and West is the negative. but if its inbetween for example in the diagram, one of the vectors is inbetween N and E but since you know they're both positive then that vector is going in the positive direction. Now look at Vector B, its going S and W. Since we know they're both negative then we can determine that Vector B is going in the negative direction.
Wait a second! What if the vector goes inbetween a negative and a positive?
Well for example if a vector goes inbetween N and W then it would be considered a positive because the N is more dominant the same can be said for S and E because it will be negative because the South is more dominant.
Well anyway we're here to determine how to add a vector but before we can do that we must first find out what a vector is.
From http://zonalandeducation.com/mstm/physics/mechanics/vectors/vectors.html it states that a vector is a a quatity that has two aspects which has a size, or magnitude, and direction.
So in absolute simple words it pretty much means a straight line.
but it can get more complicated when you add more vectors to other vectors. But before we do that once again we have to find out where the positve sectors are.
As you can see from the diagram North and East is the positive and South and West is the negative. but if its inbetween for example in the diagram, one of the vectors is inbetween N and E but since you know they're both positive then that vector is going in the positive direction. Now look at Vector B, its going S and W. Since we know they're both negative then we can determine that Vector B is going in the negative direction.
Wait a second! What if the vector goes inbetween a negative and a positive?
Well for example if a vector goes inbetween N and W then it would be considered a positive because the N is more dominant the same can be said for S and E because it will be negative because the South is more dominant.
Deriving d = v2Δt - 1/2aΔt^2
To derive the equation d = v2Δt - 1/2aΔt^2 you must first substitute v1 into Equation 2.
Equation #2:
d = 1/2(v1+v2)Δt
It can easily done by doing this:
d = 1/2(v2+v1)Δt
d = 1/2(v2+v2=aΔt)Δt
Which would therefore create:
d = v2Δt = 1/2aΔt^2
You can also use an almost similar method to derive d =v1Δt+1/2aΔt^2
Substitute the expression for v2 into Equation #2:
d = 1/2(v2+v1)Δt
d = 1/2(v1+aΔt+v1)Δt
Which would therefore get:
d = v1Δt+1/2aΔt^2
Equation #2:
d = 1/2(v1+v2)Δt
It can easily done by doing this:
d = 1/2(v2+v1)Δt
d = 1/2(v2+v2=aΔt)Δt
Which would therefore create:
d = v2Δt = 1/2aΔt^2
You can also use an almost similar method to derive d =v1Δt+1/2aΔt^2
Substitute the expression for v2 into Equation #2:
d = 1/2(v2+v1)Δt
d = 1/2(v1+aΔt+v1)Δt
Which would therefore get:
d = v1Δt+1/2aΔt^2
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